More problems involving energy changes in nuclear reactions
Posted by Jim Clark on 20th May and posted in Tutorial
| Problem | How much energy is lost or gained when a mole of cobalt-60 undergoes beta decay: 27Co60 => -1e0 + 28Ni60. The masses of 27Co60 and 28Ni60 are 59.9338 AMU and 59.9308 AMU. |
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| Solution | mass change | = mass of Ni – mass of Co = 59.9308 AMU – 59.9338 AMU = -.0030 AMU. |
| mass change per mole | = -.0030 g | |
| energy change | = mc2 = -.0030 g (3.00 E8 m/s)2 (1 kg/1000g) = -2.7 E 11 kg m2/ s2 = -2.7 E 11 J | |
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